Author Topic: Group rides: Spring 2009  (Read 43787 times)

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Offline Sal Atticum

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Group rides: Spring 2009
« on: April 11, 2009, 08:02:11 pm »
Quote from: Guardrail
Post up any group rides going on.

Give a,
When:
Where: (to and from where)
How Long:
Type: (Fun, No drop, Training)
Type of bike you're RECOMMENDING! (Fixed, MTB, Road etc. etc. etc.)

Quick tip:  When you are logged in, you can click "Notify" at the top of this topic in order to be emailed whenever there is a new post.  This way you can stay abreast of which rides are going out (assuming you check your email more often than you visit the site).
« Last Edit: August 24, 2009, 02:36:10 pm by Sal Atticum »
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Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #1 on: April 11, 2009, 08:05:54 pm »
I know tomorrow is Easter and all, but if the weather is as nice as it was today, I'm going to go for a ride sometime in the late afternoon.  If you'd like to join in, let me know.

Estimated departure: 5 or 6 pm
Meeting place: Either downtown or the Union
Where to: Depends on which direction the wind blows
How long: An hour or longer
Type: Whatever
Bicycle: Ro-Ad
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Offline sanders

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Re: Practice Thread
« Reply #2 on: April 14, 2009, 08:33:59 pm »
Group ride :headbang: to ski and bike, then who knows where  :dontknow: about 2:30 tomorrow.
Alone you are an athlete but on a bike you are a rocket

Offline Mario

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Re: Group rides: Spring 2009
« Reply #3 on: April 28, 2009, 12:12:21 pm »
Ride today, Tu 04/28, at the Union at 5pm
Planning to go about 2 hours-easy to medium pace going South first, into the wind
Helmets required
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline sanders

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Re: Group rides: Spring 2009
« Reply #4 on: April 28, 2009, 01:46:56 pm »
im acutally not going to be able to make it but tomorrow
Alone you are an athlete but on a bike you are a rocket

Offline DERINGER

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Re: Group rides: Spring 2009
« Reply #5 on: April 30, 2009, 05:22:21 pm »
I'm just getting into biking and will be around all next week (May 4th-May 10th) and possibly the summer in GF. Anyone going on rides next week, post 'em and I'll be there.
"My Shit's fucked up" -Warren Zevon

Offline Mario

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Re: Group rides: Spring 2009
« Reply #6 on: May 01, 2009, 10:44:57 am »
Group ride today-easy about 20 miles, unless the weather does not cooperate
Meet at the front of the Union at 5pm.
Helmets required
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Plantains

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Re: Group rides: Spring 2009
« Reply #7 on: May 01, 2009, 04:22:14 pm »
deringer... u comin?
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Offline DERINGER

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Re: Group rides: Spring 2009
« Reply #8 on: May 01, 2009, 08:27:51 pm »
If I was in town, I woulda been there. I'm gonna be in town Monday night.
"My Shit's fucked up" -Warren Zevon

Offline Alaska Unicyclist

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Re: Group rides: Spring 2009
« Reply #9 on: May 03, 2009, 01:35:09 pm »
hey all group ride 5pm union? its a beautiful day out and we should take full advantage of it. :) 5/3/09
"It never gets easier, you just get faster" - Greg Lemond

Offline Plantains

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Re: Group rides: Spring 2009
« Reply #10 on: May 03, 2009, 02:14:45 pm »
we moved it to 3pm
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Offline Hollywood

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Re: Group rides: Spring 2009
« Reply #11 on: May 04, 2009, 09:26:51 am »
Group ride
Today (5/4/09)
Leaving from Union at 5pm
~90-120 min (maybe some Merrifield or Airport loop [depending on which direction the wind is coming from])
Helmets required
"You can have all the heart in the world, but it doesn't mean anything if you haven't got the legs"

Offline Mario

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Re: Group rides: Spring 2009
« Reply #12 on: May 04, 2009, 09:48:25 am »
I will not be able to make it by 5.The earliest I can go is 5:30
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Alaska Unicyclist

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Re: Group rides: Spring 2009
« Reply #13 on: May 04, 2009, 10:07:08 am »
i'll be where i need to be when i need to be. you can quote me on that if you wish
sincerely,
DF
"It never gets easier, you just get faster" - Greg Lemond

Offline Hollywood

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Re: Group rides: Spring 2009
« Reply #14 on: May 04, 2009, 11:09:13 am »
All right, 5:30 it is!
"You can have all the heart in the world, but it doesn't mean anything if you haven't got the legs"

Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #15 on: May 04, 2009, 03:58:59 pm »
Swate.  Hope all the new people are listening...
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Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #16 on: May 04, 2009, 04:01:20 pm »
I propose an around-town ride at around 7 on Wednesday.

(I changed that because no-drop is usually Thursday.)
« Last Edit: May 04, 2009, 05:09:49 pm by Sal Atticum »
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Offline Mario

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Re: Group rides: Spring 2009
« Reply #17 on: May 05, 2009, 01:34:31 pm »
Ride today 5/5 meet at the Union at 5:30
Easy ride of about 1.5-2 hours
Helmets required
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline DERINGER

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Re: Group rides: Spring 2009
« Reply #18 on: May 05, 2009, 02:40:45 pm »
I'm down for Wednesday....but my bike is in the shop until at least thursday. if I can get a bike, count me in.
"My Shit's fucked up" -Warren Zevon

Offline Alaska Unicyclist

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Re: Group rides: Spring 2009
« Reply #19 on: May 05, 2009, 03:38:15 pm »
i wont be there, i have hw to do
"It never gets easier, you just get faster" - Greg Lemond

Offline Mario

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Re: Group rides: Spring 2009
« Reply #20 on: May 05, 2009, 04:19:00 pm »
HW  is overrated :p
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Alaska Unicyclist

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Re: Group rides: Spring 2009
« Reply #21 on: May 05, 2009, 04:22:37 pm »
ya it is
"It never gets easier, you just get faster" - Greg Lemond

Offline Flutterbye

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Re: Group rides: Spring 2009
« Reply #22 on: May 05, 2009, 05:31:34 pm »
can't.... count me in for maybe wed and surely thursday
If you're overweight, we're towing away your car.

Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #23 on: May 06, 2009, 08:57:30 am »
I propose an around-town ride at around 7 on Wednesday.

(I changed that because no-drop is usually Thursday.)

Wednesday is a go.  Meet out front of the Union in your finest suits.
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Offline Alaska Unicyclist

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Re: Group rides: Spring 2009
« Reply #24 on: May 06, 2009, 09:37:51 am »
i cant go. i have class i can probably go for a ride mid- afternoon if anyone wants to join me
"It never gets easier, you just get faster" - Greg Lemond

Offline Plantains

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Re: Group rides: Spring 2009
« Reply #25 on: May 06, 2009, 10:14:21 am »
I can't go either now... sad.
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Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #26 on: May 06, 2009, 12:14:56 pm »
Is there anyone who IS going to make it?
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Offline sanders

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Re: Group rides: Spring 2009
« Reply #27 on: May 06, 2009, 03:52:05 pm »
i have lab at seven so i never was able to make it. not to mention i have a sprained ankle
Alone you are an athlete but on a bike you are a rocket

Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #28 on: May 06, 2009, 05:41:10 pm »
i have lab at seven so i never was able to make it. not to mention i have a sprained ankle

No worries dude.  I wasn't actually trying to make you feel guilty.

BUT...it's so beautiful outside.  You're missing out :D
JUST EXTRA POLISH. I DO SOME WORK WITH EXCELL SO I KEEP THE CAPS LOCK ON :-P

Offline Mario

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Re: Group rides: Spring 2009
« Reply #29 on: May 07, 2009, 09:04:17 am »
Ride today, 5/7, at 5pm at the Union.
Easy to moderate pace , about 1.5-2 hours.
Helmet required.
Come and enjoy the ride!
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #30 on: May 07, 2009, 11:21:32 am »
Road ride?

I will not be able to attend in any case.
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Offline Mario

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Re: Group rides: Spring 2009
« Reply #31 on: May 07, 2009, 02:27:47 pm »
yes, it is a road ride.Bring warm clothing !!


worms are no fun on bikes. *edited by guardrail*
« Last Edit: May 07, 2009, 03:10:33 pm by Guardrail »
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Alaska Unicyclist

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Re: Group rides: Spring 2009
« Reply #32 on: May 07, 2009, 04:10:51 pm »
I'll c u thurr
"It never gets easier, you just get faster" - Greg Lemond

Offline Mario

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Re: Group rides: Spring 2009
« Reply #33 on: May 08, 2009, 11:08:59 am »
Road Ride today,5/8, at 4pm in front of the Union
About 2 hours. Bring worm cloths, it is cold!!
Helmets required.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Casey

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Re: Group rides: Spring 2009
« Reply #34 on: May 08, 2009, 01:45:17 pm »
Can't go, work until 6!

Offline Alaska Unicyclist

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Re: Group rides: Spring 2009
« Reply #35 on: May 08, 2009, 03:07:08 pm »
i probably can't go either, i will be out of town for the evening.
"It never gets easier, you just get faster" - Greg Lemond

Offline Mario

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Re: Group rides: Spring 2009
« Reply #36 on: May 10, 2009, 11:44:54 am »
Lets ride at 3pm.
Meet at the Union.
long ride 2.5-3 hours.
helmets required.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Casey

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Re: Group rides: Spring 2009
« Reply #37 on: May 10, 2009, 01:17:33 pm »
Ill be there!

Offline Mario

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Re: Group rides: Spring 2009
« Reply #38 on: May 11, 2009, 08:24:57 am »
Road ride,5/11, at 4pm in front of the Union
About 1.5-2 hours
Helmets required
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #39 on: May 11, 2009, 09:15:54 am »
Crap, I can't get out until 5:30.
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Offline curlingDave

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Re: Group rides: Spring 2009
« Reply #40 on: May 11, 2009, 01:22:06 pm »
Test at 3:15  :disgust: :shitstorm:
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Offline Casey

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Re: Group rides: Spring 2009
« Reply #41 on: May 12, 2009, 10:44:27 am »
Group ride today? weather seems nice!

Offline Mario

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Re: Group rides: Spring 2009
« Reply #42 on: May 12, 2009, 12:33:06 pm »
I don't think we will have a ride today. The weather forecast talks about storms this afternoon.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Hollywood

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Re: Group rides: Spring 2009
« Reply #43 on: May 12, 2009, 01:15:36 pm »
OH! Oh, Mario...You're always...forecasting and stuff :yost:
"You can have all the heart in the world, but it doesn't mean anything if you haven't got the legs"

Offline Alaska Unicyclist

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Re: Group rides: Spring 2009
« Reply #44 on: May 12, 2009, 01:58:13 pm »
storms didnt stop us YESTERDAY! just kidding i think im putting my bike in a box today and shipping it to the last frontier... so i may not get to ride with you guys until next fall... :(
"It never gets easier, you just get faster" - Greg Lemond

Offline Hollywood

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Re: Group rides: Spring 2009
« Reply #45 on: May 12, 2009, 02:25:56 pm »
NOOOOOOOOOOOOOOO! This is truly the end of an era.  The reign of the Specialized Sequoia Elite is coming to a close :(
"You can have all the heart in the world, but it doesn't mean anything if you haven't got the legs"

Offline Alaska Unicyclist

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Re: Group rides: Spring 2009
« Reply #46 on: May 12, 2009, 03:25:11 pm »
the MARK I & II still lives on
"It never gets easier, you just get faster" - Greg Lemond

Offline Plantains

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Re: Group rides: Spring 2009
« Reply #47 on: May 13, 2009, 11:10:45 am »
1. It sounds cheesy, but since we're losing a couple fellows we should get a team pic with our championship trophy.
2. Logan, you could ride my fixed gear (which I can make single speed) for the few days if you want to. Its a 44x16 which might suck with wind. (well fixed it sucks with a tailwind, single speed it sucks only a little in both directions) It would be like riding a 53x19 or a 39x14. Only front brakes tho.
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Offline Alaska Unicyclist

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Re: Group rides: Spring 2009
« Reply #48 on: May 13, 2009, 11:38:00 am »
i don't think i have time to ride anymore... i have finals and a stage check and all this other school stuff.
"It never gets easier, you just get faster" - Greg Lemond

Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #49 on: May 13, 2009, 11:38:50 am »
Any chance the weather will be decent this afternoon?
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Offline Casey

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Re: Group rides: Spring 2009
« Reply #50 on: May 13, 2009, 01:45:09 pm »
Probably not! Its snowing in Montana and probably head our way lol

Offline Plantains

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Re: Group rides: Spring 2009
« Reply #51 on: May 14, 2009, 07:17:17 pm »
Bored. DOne with Finals. anyone wanna go for a cruise around town? I feel like riding my urbanian.

Call or text.
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Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #52 on: May 15, 2009, 10:16:31 am »
Ride today at 1:30 (time negotiable, post up).
Out into the wind.
Helmets required.
If I don't hear from anyone I'll go on my own schedule and won't stop by the Union.
« Last Edit: May 15, 2009, 10:17:24 am by Sal Atticum »
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Offline Mario

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Re: Group rides: Spring 2009
« Reply #53 on: May 15, 2009, 10:32:13 am »
If I were you, I would check the weather first. It looks like it's going to rain just as you plan to go.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #54 on: May 15, 2009, 10:41:01 am »
It looked to me like it was going to be worse later in the day, so I was trying to go earlier.
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Offline Mario

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Re: Group rides: Spring 2009
« Reply #55 on: May 15, 2009, 12:06:46 pm »
I know man. I wish I could have gone at 9:00am  when the weather was nice, but I had a final in the morning and I have another one at 1:00 :-(
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Plantains

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Re: Group rides: Spring 2009
« Reply #56 on: May 15, 2009, 12:31:54 pm »
Yeah... rain around 2ish.

Edit: The storm looks like it has more of an easterly flow than anticipated and may end up completely pushing off around 5ish.
« Last Edit: May 15, 2009, 01:01:02 pm by Guardrail »
Alaska Unicyclist: if you ban me, i'll set your complex on fire.... just a heads up

Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #57 on: May 15, 2009, 01:21:24 pm »
Never mind, I already went.

People are being dicks on university and parking in the bike lane, by the way.
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Offline Plantains

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Re: Group rides: Spring 2009
« Reply #58 on: May 15, 2009, 03:46:12 pm »
Lets go steal their license plates.
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Offline Mario

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Re: Group rides: Spring 2009
« Reply #59 on: May 16, 2009, 10:55:13 am »
Group ride at 2:00pm leaving from the Union.
About 2 hours, easy ride. We have Church at 4:45, so we need to be on time with departure and return.
Helmets required.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline curlingDave

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Re: Group rides: Spring 2009
« Reply #60 on: May 16, 2009, 01:04:20 pm »
I'm game.
Life is complex.  It has a real part and an imaginary part.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #61 on: May 16, 2009, 08:31:38 pm »
I'm going for a long (around 2.5 hours) easy ride tomorrow morning at about 7:00am. If anybody is interested, give me a call or send me a personal message. Thanks!
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #62 on: May 21, 2009, 03:43:29 pm »
An easy ride tonight at 6pm
Meet at the union.Probably 1.5 hours,easy
Helmets required.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Plantains

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Re: Group rides: Spring 2009
« Reply #63 on: May 21, 2009, 04:50:20 pm »
see ya there buddy
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Offline Mario

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Re: Group rides: Spring 2009
« Reply #64 on: May 23, 2009, 09:55:58 am »
Easy ride today at 3pm leaving from the Union.
Some two hours of ride in a beautiful weather.
Be there or be camping! Don't forget a helmet and a snack!
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #65 on: May 23, 2009, 08:36:51 pm »
Another easy but longer ride tomorrow, Sunday , May 24 at 11:30 at the Union.
Bring something to drink and food-you will need that!
Of course, don't forget your helmet.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #66 on: May 26, 2009, 09:36:22 am »
Ride today at 6pm in front of the union. I will be going for about 1.5 hours, doing sprints. Anybody is welcome to join.
Helmets required.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Plantains

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Re: Group rides: Spring 2009
« Reply #67 on: May 26, 2009, 10:54:39 am »
wont make it wario... emmy and i have plans.
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Offline Mario

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Re: Group rides: Spring 2009
« Reply #68 on: May 26, 2009, 12:55:55 pm »
What about the plans for you and me ?? :crybaby2:
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Once a Runner

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Re: Group rides: Spring 2009
« Reply #69 on: May 26, 2009, 02:00:39 pm »
I will be riding today but I don't think I am up for sprints just yet (going to be working on my base and threshold for awhile)

Offline Mario

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Re: Group rides: Spring 2009
« Reply #70 on: May 28, 2009, 06:45:34 am »
Ride today 5:30, about 1.5 hours. Meet at the union.
Let's enjoy the weather!
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #71 on: May 29, 2009, 01:06:44 pm »
I wish I could have gone.  I doubt I'll be able to go today. :/

By the way, you know what I'm doing at 6:45 in the morning?  Sleeping, that's what.
JUST EXTRA POLISH. I DO SOME WORK WITH EXCELL SO I KEEP THE CAPS LOCK ON :-P

Offline Alaska Unicyclist

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Re: Group rides: Spring 2009
« Reply #72 on: May 29, 2009, 09:52:03 pm »
i'll be riding tomorrow at 12.. going about 14 miles, meet at my house
"It never gets easier, you just get faster" - Greg Lemond

Offline Plantains

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Re: Group rides: Spring 2009
« Reply #73 on: May 29, 2009, 10:50:18 pm »
i'll be riding tomorrow at 12.. going about 14 miles, meet at my house

Post of the year!
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Offline Mario

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Re: Group rides: Spring 2009
« Reply #74 on: May 29, 2009, 11:21:39 pm »
Watch us flying in, above your head about 11:30  :undcc:
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #75 on: June 03, 2009, 12:07:46 pm »
Ride today, 06/03: Meeting at 6:30 at the Merifield, right after crossing the railroad. There is going to be Time Trial ride (10 or 20 miles). Everybody is welcome. It takes about 30-40 minutes to get to the Merifield from the Union, so you have to leave at the appropriate time. Hope to see you there!
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Gus Gus

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Re: Group rides: Spring 2009
« Reply #76 on: June 03, 2009, 02:07:27 pm »
Hey i'm fairly new here, only been on a few rides with you guys, and was going to see if anyone was planning to meet at the union to head down there? I'd like to jump in on this ride, -Adam

Offline Once a Runner

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Re: Group rides: Spring 2009
« Reply #77 on: June 03, 2009, 02:14:56 pm »
I will be going by the Union a little before 6. We can head out from there.

Offline Plantains

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Re: Group rides: Spring 2009
« Reply #78 on: June 03, 2009, 03:03:19 pm »
Yeah guys... I'll meet you at the union at 5:45 and roll out there with you. Adam, (or kyle) if you guys aren't up for TTing I won't be doing it so I'll just be riding back into town... all are welcome. Helmets required, and if you're on a TT bike please make sure you DO NOT ride on your aero bars during any portion of group riding.
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Offline Mario

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Re: Group rides: Spring 2009
« Reply #79 on: June 05, 2009, 10:58:41 am »
Easy ride today at 5:30, meet at the union. A little bit over an hour ride with the helmet on your head  :undcc:
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Plantains

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Re: Group rides: Spring 2009
« Reply #80 on: June 05, 2009, 01:14:25 pm »
I has test.
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Offline Mario

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Re: Group rides: Spring 2009
« Reply #81 on: June 07, 2009, 08:51:25 am »
If anybody is interested I will swing by the Union today, Sunday, at 11:30 for an easy ride ,1.5 hours or so.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Once a Runner

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Re: Group rides: Spring 2009
« Reply #82 on: June 07, 2009, 09:10:16 am »
Just finished my long run so I don't think I will be joining you...I think I am going out later this afternoon after some recov time to get some easy riding miles in

Offline Hollywood

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Re: Group rides: Spring 2009
« Reply #83 on: June 09, 2009, 02:41:40 pm »
Kyle, I'm just happy to see your shirt is on in your picture.
"You can have all the heart in the world, but it doesn't mean anything if you haven't got the legs"

Offline Plantains

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Re: Group rides: Spring 2009
« Reply #84 on: June 09, 2009, 03:10:23 pm »
u too jesus.
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Offline Hollywood

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Re: Group rides: Spring 2009
« Reply #85 on: June 10, 2009, 08:53:18 am »
Group ride today
Leaving from Ski and Bike at 2pm
About 2 hours, easy-moderate intensity
YEAH!
"You can have all the heart in the world, but it doesn't mean anything if you haven't got the legs"

Offline Mario

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Re: Group rides: Spring 2009
« Reply #86 on: June 10, 2009, 09:15:40 am »
Or the alternate ride for people that are interested:
Ride today, 06/10: Meeting at 6:30 at the Merifield, right after crossing the railroad. There is going to be Time Trial ride (10). Everybody is welcome. It takes about 30-40 minutes to get to the Merifield from the Union, so you have to leave at the appropriate time. Hope to see you there!
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Hollywood

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Re: Group rides: Spring 2009
« Reply #87 on: June 10, 2009, 09:36:50 am »
OR BOTH!
GAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAH! :o
"You can have all the heart in the world, but it doesn't mean anything if you haven't got the legs"

Offline Once a Runner

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Re: Group rides: Spring 2009
« Reply #88 on: June 10, 2009, 09:39:33 am »
I will be there for the TT (Mario, is it possible to swing by your place and try out the aeros?)

btw: Hollywood, I said it before and I'll say it again: "the only way to get ahead in life is to take your shirt off every once in awhile" I am just waiting for my big break!

Offline Hollywood

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Re: Group rides: Spring 2009
« Reply #89 on: June 10, 2009, 10:58:34 am »
Well if that's the case, i might just to the TT topless.
"You can have all the heart in the world, but it doesn't mean anything if you haven't got the legs"

Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #90 on: June 10, 2009, 03:21:27 pm »
Or the alternate ride for people that are interested:
Ride today, 06/10: Meeting at 6:30 at the Merifield, right after crossing the railroad. There is going to be Time Trial ride (10). Everybody is welcome. It takes about 30-40 minutes to get to the Merifield from the Union, so you have to leave at the appropriate time. Hope to see you there!

Are you leaving from the Union at 5:45, or from your place?
JUST EXTRA POLISH. I DO SOME WORK WITH EXCELL SO I KEEP THE CAPS LOCK ON :-P

Offline Mario

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Re: Group rides: Spring 2009
« Reply #91 on: June 10, 2009, 03:40:34 pm »
Or the alternate ride for people that are interested:
Ride today, 06/10: Meeting at 6:30 at the Merifield, right after crossing the railroad. There is going to be Time Trial ride (10). Everybody is welcome. It takes about 30-40 minutes to get to the Merifield from the Union, so you have to leave at the appropriate time. Hope to see you there!

Are you leaving from the Union at 5:45, or from your place?

I'm leaving form my place around 5:30 because I have a one hour worm up with some intervals in it. you can join me if you wish but I will have to go according to my Heart Rate.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #92 on: June 10, 2009, 04:21:26 pm »
Okay then, does anyone else want to ride around 6 tonight?
JUST EXTRA POLISH. I DO SOME WORK WITH EXCELL SO I KEEP THE CAPS LOCK ON :-P

Offline Plantains

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Re: Group rides: Spring 2009
« Reply #93 on: June 10, 2009, 05:18:51 pm »
Yes but I cannot for I have been in a low oxygen environment and am forbidden by "the man" to exercise.
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Offline Gus Gus

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Re: Group rides: Spring 2009
« Reply #94 on: June 12, 2009, 12:03:02 pm »
Whats up everybody
I've got to go enjoy a ride today
i'll be at the Union 5:30
Going where ever the wind blows
moderate - great ride

Offline Mario

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Re: Group rides: Spring 2009
« Reply #95 on: June 12, 2009, 01:21:03 pm »
I might show up for an easy spin, but I don't promise.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Hollywood

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Re: Group rides: Spring 2009
« Reply #96 on: June 12, 2009, 04:03:18 pm »
I have a going away party to attend to :(
"You can have all the heart in the world, but it doesn't mean anything if you haven't got the legs"

Offline curlingDave

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Re: Group rides: Spring 2009
« Reply #97 on: June 19, 2009, 03:34:10 pm »
Going for an easy-moderate ride, 1.5 - 2 hours tomorrow morning at 7:15 leaving from the union.
Life is complex.  It has a real part and an imaginary part.

Offline Plantains

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Re: Group rides: Spring 2009
« Reply #98 on: June 19, 2009, 06:06:40 pm »
Damn there's a 7:15 now? When did we get that?
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Offline curlingDave

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Re: Group rides: Spring 2009
« Reply #99 on: June 19, 2009, 10:57:25 pm »
Couldn't decide between 7:00 and 7:30, so I interpolated :D
Life is complex.  It has a real part and an imaginary part.

Offline Plantains

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Re: Group rides: Spring 2009
« Reply #100 on: June 20, 2009, 12:10:13 am »
lol... thats cool.

interpolated is a good word.
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Offline Hollywood

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Re: Group rides: Spring 2009
« Reply #101 on: June 22, 2009, 01:35:06 pm »
anyone up for a longer (~2hr) easy ride today at 5:30?...leaving from the union?
"You can have all the heart in the world, but it doesn't mean anything if you haven't got the legs"

Offline Casey

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Re: Group rides: Spring 2009
« Reply #102 on: June 22, 2009, 01:50:37 pm »
i am.

Offline Plantains

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Re: Group rides: Spring 2009
« Reply #103 on: June 22, 2009, 02:12:19 pm »
yeah... I think I'm finally feeling it.
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Offline Gus Gus

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Re: Group rides: Spring 2009
« Reply #104 on: June 22, 2009, 02:44:11 pm »
I'm going to have to pass today. Unless you plan on riding by Fargo... then I'm all in.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #105 on: June 22, 2009, 04:02:29 pm »
I have well deserved day off today :-)
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Hollywood

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Re: Group rides: Spring 2009
« Reply #106 on: June 22, 2009, 04:52:42 pm »
"Well deserved"? That's debatable.
"You can have all the heart in the world, but it doesn't mean anything if you haven't got the legs"

Offline Mario

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Re: Group rides: Spring 2009
« Reply #107 on: June 22, 2009, 06:42:43 pm »
You are debatable!
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline curlingDave

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Re: Group rides: Spring 2009
« Reply #108 on: June 22, 2009, 10:26:03 pm »
That's what she said!

Meh...no...that doesn't really work.
Life is complex.  It has a real part and an imaginary part.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #109 on: June 24, 2009, 08:43:01 am »
Easy ride today, at 5 leaving from the Union. About 1.5 hours of enjoyable ride in beautiful weather. You better be there or we will come and find you!! Don't waste such a beautiful day!!
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline curlingDave

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Re: Group rides: Spring 2009
« Reply #110 on: June 26, 2009, 06:27:32 pm »
7:15 tomorrow morning 1.5 hours, if it's not raining and you're not sleeping.  Both are likely.
Life is complex.  It has a real part and an imaginary part.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #111 on: June 26, 2009, 11:55:29 pm »
As of right now it looks like it might rain.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #112 on: June 29, 2009, 10:06:15 am »
Easy , about one hour ride today at 6 leaving from the Union.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

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Re: Group rides: Spring 2009
« Reply #113 on: June 29, 2009, 02:42:59 pm »
I'll see you there, DAWG
"You can have all the heart in the world, but it doesn't mean anything if you haven't got the legs"

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Re: Group rides: Spring 2009
« Reply #114 on: July 01, 2009, 02:35:42 pm »
Time trial ,today , starting at 6:30 at Marryifeld (I have no clue how to spell it). Hope to see you there. It's beautiful weather.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #115 on: July 06, 2009, 01:49:32 pm »
Easy ride today, July 6, about one hour long, leaving form the union at 6:30. Come and enjoy bike riding.   
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline curlingDave

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Re: Group rides: Spring 2009
« Reply #116 on: July 07, 2009, 05:13:44 pm »
7:30, a couple hours moderate/easy.
Life is complex.  It has a real part and an imaginary part.

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Re: Group rides: Spring 2009
« Reply #117 on: July 09, 2009, 11:22:57 pm »
I have a long three hours ride tomorrow, at fairly easy pace. If you want to join me , let me know here or send me personal message. I will be going sometime around 11-12.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

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Re: Group rides: Spring 2009
« Reply #118 on: July 11, 2009, 09:49:10 pm »
long, easy-moderate, up to 3 hours ride, tomorrow 7/12. Leaving form the Union about 12 (pending the weather conditions ). I will give upgrade tomorrow about 11. Don't forget food and drinks with you!
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #119 on: July 12, 2009, 10:58:25 am »
Noon it is. Let's enjoy the day!
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #120 on: July 13, 2009, 10:47:30 am »
An easy one hour ride today at 6 leaving form the Union (weather pending, there is a storm coming our way)
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Once a Runner

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Re: Group rides: Spring 2009
« Reply #121 on: July 13, 2009, 11:16:06 am »
I'm game

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Re: Group rides: Spring 2009
« Reply #122 on: July 13, 2009, 05:09:33 pm »
I'm there, brah!
"You can have all the heart in the world, but it doesn't mean anything if you haven't got the legs"

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Re: Group rides: Spring 2009
« Reply #123 on: July 16, 2009, 11:07:52 am »
Moderate ride today, 1.5-2 hours long. Meeting at the Union at 6.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #124 on: July 16, 2009, 01:06:20 pm »
May be able to make it.
JUST EXTRA POLISH. I DO SOME WORK WITH EXCELL SO I KEEP THE CAPS LOCK ON :-P

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Re: Group rides: Spring 2009
« Reply #125 on: July 16, 2009, 02:03:13 pm »
not sure if i will be there, i will be riding but i do not know if this time will work yet

Offline Mario

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Re: Group rides: Spring 2009
« Reply #126 on: July 17, 2009, 07:54:48 am »
Short, easy, pre-race ride today at 1:00 in front of the Union. Post here if you are going to be there. If I iwll not see post, I will not come to the Union!   :undcc:
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #127 on: July 19, 2009, 02:35:50 pm »
How far did we go the other day?  I did not have my computer with me.
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Re: Group rides: Spring 2009
« Reply #128 on: July 20, 2009, 10:16:50 am »
I think we have gone about 30 miles but I can double check tonight when I come back home.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #129 on: July 21, 2009, 09:35:06 am »
Longer ride today, 2 hours, mostly easy but with few 2-3 min harder efforts in it. Meet at the Union at 6.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Mario

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Re: Group rides: Spring 2009
« Reply #130 on: July 22, 2009, 01:09:01 pm »
Time trial today at 6:30 at Merifield. It looks like a nice weather ,so take an advantage of it.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #131 on: July 23, 2009, 02:57:49 pm »
Anyone up for a ride today around 6?  Otherwise I may go brave the Greenway trails.
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Re: Group rides: Spring 2009
« Reply #132 on: July 23, 2009, 03:02:06 pm »
Going to be BBQ-ing with Mr. Downs!
"You can have all the heart in the world, but it doesn't mean anything if you haven't got the legs"

Offline Mario

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Re: Group rides: Spring 2009
« Reply #133 on: July 27, 2009, 02:02:01 pm »
Long, 2hours recovery ride starting at 6 from the Union.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

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Re: Group rides: Spring 2009
« Reply #134 on: July 30, 2009, 11:19:14 am »
its been a while since i've seen some of you fools, and some I've never had the pleasure..I'll be in town this weekend (Sat and Sunday) riding dirty with a brand new, well at least to me, Bianchi.    I won't really have internet anywhere. But I'll try, so call or text me with rides

robert
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"My Shit's fucked up" -Warren Zevon

Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #135 on: August 01, 2009, 01:41:44 pm »
I'll be going out for a ride within the next hour or so.  Ring me up if you want in.
JUST EXTRA POLISH. I DO SOME WORK WITH EXCELL SO I KEEP THE CAPS LOCK ON :-P

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Re: Group rides: Spring 2009
« Reply #136 on: August 02, 2009, 01:52:20 pm »
meet me for a easy ride 16 18 Mph   i'm kinda hungover    i'll be there about 4pm
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Re: Group rides: Spring 2009
« Reply #137 on: August 02, 2009, 02:13:00 pm »
@the union
"My Shit's fucked up" -Warren Zevon

Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #138 on: August 09, 2009, 12:16:06 pm »
If anyone is around who wants to ride today but avoid the Mario Train (because he's doing a workout I assume), I am hoping to go out at 5 or 6 tonight if the weather holds.
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Re: Group rides: Spring 2009
« Reply #139 on: August 09, 2009, 02:55:12 pm »
Mario is in Washington. I'll text you.
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Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #140 on: August 09, 2009, 03:26:45 pm »
Mario is in Washington. I'll text you.

That doesn't change my plans to go ride, but yes I should have known that.

By the way, I don't technically have a texting plan, so if I could just get you to move your desk about six inches backward, yeah, that'd be great.
JUST EXTRA POLISH. I DO SOME WORK WITH EXCELL SO I KEEP THE CAPS LOCK ON :-P

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Re: Group rides: Spring 2009
« Reply #141 on: August 10, 2009, 12:33:32 am »
This is interesting to know. I will now refrain from texting you.
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Offline Mario

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Re: Group rides: Spring 2009
« Reply #142 on: August 18, 2009, 09:08:11 am »
Group ride today, easy to moderate pace, nothing hard, about 2 hours long. Meet at the Union at 5:30.  :mario: Helmets, spare tubes, and happy attitude required!   :tongue3:
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #143 on: August 18, 2009, 04:45:35 pm »
I'll be there.
JUST EXTRA POLISH. I DO SOME WORK WITH EXCELL SO I KEEP THE CAPS LOCK ON :-P

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Re: Group rides: Spring 2009
« Reply #144 on: August 19, 2009, 12:25:57 am »
"Yeah...I prob'ly swim with buoy to give legs a rest or something..." <---Mario
"You can have all the heart in the world, but it doesn't mean anything if you haven't got the legs"

Offline curlingDave

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Re: Group rides: Spring 2009
« Reply #145 on: August 19, 2009, 08:20:10 am »
How about floaty wings? :blob3:
Life is complex.  It has a real part and an imaginary part.

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Re: Group rides: Spring 2009
« Reply #146 on: August 19, 2009, 10:46:19 am »
You have no idea how long it took us to get Mario swimming without those things :P
"You can have all the heart in the world, but it doesn't mean anything if you haven't got the legs"

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Re: Group rides: Spring 2009
« Reply #147 on: August 19, 2009, 01:46:09 pm »
He swims without those now? What do they call those things in Poland wario?
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Re: Group rides: Spring 2009
« Reply #148 on: August 19, 2009, 03:09:15 pm »
Anyone want to go mountain biking...

ON UNIVERSITY AVENUE! Seriously... wtf?
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Offline curlingDave

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Re: Group rides: Spring 2009
« Reply #149 on: August 19, 2009, 03:29:14 pm »
Me pretending I'm an incoming freshman:  "North Dakota can't be that bad.  Wait a minute, my university is on a freakin gravel road..."  :(
Life is complex.  It has a real part and an imaginary part.

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Re: Group rides: Spring 2009
« Reply #150 on: August 19, 2009, 03:34:27 pm »
Wario doesn't know what those things are called.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

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Re: Group rides: Spring 2009
« Reply #151 on: August 19, 2009, 03:44:10 pm »
Theres one in your avatar. Facepalm.
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Offline Cycleguy

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Re: Group rides: Spring 2009
« Reply #152 on: August 23, 2009, 03:22:55 pm »
Hello, i am a freshman this year, and i am interested in joining, will there be a ride monday or tuesday the first week of classes, otherwise i will stop by the booth on wedsday, thanks.

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Re: Group rides: Spring 2009
« Reply #153 on: August 23, 2009, 06:31:25 pm »
Hello, i am a freshman this year, and i am interested in joining, will there be a ride monday or tuesday the first week of classes, otherwise i will stop by the booth on wedsday, thanks.

Joe: Check ur private messages.
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Offline Mario

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Re: Group rides: Spring 2009
« Reply #154 on: August 23, 2009, 10:43:34 pm »
Ride tomorrow, Mn 24th, at 5:30 pm in front of the Union. The ride will be easy to moderate, about 1.5 hours. Everybody is welcome.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Cycleguy

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Re: Group rides: Spring 2009
« Reply #155 on: August 23, 2009, 11:06:05 pm »
darn, i won't be able to join the ride on Mn 24th because i am in Walsh and we start the floor wars at 6,

Offline Alaska Unicyclist

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Re: Group rides: Spring 2009
« Reply #156 on: August 24, 2009, 08:57:32 am »
hey cycleguy.. what floor you on in Walsh? i am in second 226B.. come on by man and say hi
and mario I'll ride with you!!
« Last Edit: August 24, 2009, 08:59:27 am by Alaska Unicyclist »
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Offline Sal Atticum

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Re: Group rides: Spring 2009
« Reply #157 on: August 24, 2009, 09:50:10 am »
Has anyone seen Johnny yet?
JUST EXTRA POLISH. I DO SOME WORK WITH EXCELL SO I KEEP THE CAPS LOCK ON :-P

Offline Mario

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Re: Group rides: Spring 2009
« Reply #158 on: August 24, 2009, 10:11:10 am »
Not me. Hope to see him soon.
The minimum number of bikes one should own is three.  The correct number is n+1, where n is the number of bikes currently owned.  This equation may also be re-written as s-1, where s is the number of bikes owned that would result in separation from your partner.

Offline Cycleguy

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Re: Group rides: Spring 2009
« Reply #159 on: August 24, 2009, 01:18:50 pm »
Hey, Alaska Unicyclist

I am on third floor 313A, yeah i will stop by

 

anything
realistic
anything